原创 like 2
JS之..顺序同步延时执行事..算了我爱你
2020.06.19 04:24
2 人喜欢
756 次阅读
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var a = [1000, 500]
var b = []
a.forEach(e => {
let c = 0
b.push(function () {
return new Promise((resolve) => {
setTimeout(() => {
console.log(e)
c++
resolve(c)
}, e);
}).then((c) => {
if (b[c] === undefined) return
b[c]()
})
})
})
b[0]()